Question

Calculate the root mean square velocity of nitrogen molecules at 25 C.

a. 515 m/s
b. 149
c . 729 got wrong
d. 297 m/s

Answer 1

\[\sqrt{\frac{3 RT }{ M }}\]

M is molar mass

Answer 2

Okay so T = 298 K, M = 14 g and r = .08

Answer 3

i get something like 2.25

Answer 4

nitrogen is N2

Answer 5

Got it
1) 23 degree c = 23+273 =296 Kelvin

2) Nitrogen (M 28) mass in this equation ( /1000) = 0.028 Kg

3) RMS velocity of N at 23 degrees c = √ (3 x R x T/M )

√ (3 x 8.31 x 296/0.028)

515