use a standard normal distribution table to find a z score such that 36% of the area under the standard normal curve is below that score.
someone please help
It's 36%. That's less than 1/2, so we seek a negative z-score. Empirical rules suggests that z = -1 puts 16% in the left tail, so we shoudl be closer to zero than z = -1. What tools have you to calculate a more precise value?
I just have a normal distribution table
A picture? It should have one tail or the other shaded.
Perfect. You just have to find the value 0.3600 in the body of the table and read the answer from the row and column labels.
would the 0.3594 count as that? I cant find a 0.3600
in that case it would be -0.36
That is a common problem. You have to decide what to do. 1) Get as close as possible, or 2) Learn to interpolate between the two closest values. I get an exact value (off a calculator) of -0.3584588. Your well-selected value of -0.36 is right on! Excellent work.
but that seems too easy, 36% works out to -0.36. is that normal?
Only a coincidence. Don't count on it happening too ofte, One is increasing and the other decreasing. It crosses at about 0.35958 but NOWHERE else.
ok, thanks!
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