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Chemistry 12 Online
OpenStudy (anonymous):

#1: Karen measures the volume of a gas at 200 K and 100 kPa. To correct her measurement to standard temperature and pressure (STP), what must she do? A. make a volume correction based on a higher pressure of 200 kPa B. make a volume correction based on a higher temperature of 273 K C. make a volume correction based on a lower pressure of 50 kPa D. make a volume correction based on a lower temperature of 73 K **my answer: B is that right?

OpenStudy (anonymous):

#2: A 3.00 L flexible container holds a sample of hydrogen gas at 153 kPa. If the pressure increases to 304 kPa and the temperature remains constant, what will the volume be? A. 0.66 L B. 1.51 L C. 2.26 L D. 4.50 L ***my answer: B is that right?

terenzreignz (terenzreignz):

No idea with 1, correct in 2

OpenStudy (anonymous):

#3: A 3.0 L container holds a sample of hydrogen gas at 300K. If the temperature decreases to 100K and the pressure remains constant, what will the volume be? A. 0.1 L B. 0.3 L C. 1.0 L D. 9.0 L **my answer: C is that right?

OpenStudy (anonymous):

okay :)

OpenStudy (anonymous):

#4: You compare the gas generated from a reaction using two antacid tablets with the gas generated from a reaction using four antacid tablets (consider the antacid as the limiting reagent). At constant pressure and temperature, how do the volumes of the gases compare? A. The gas generated by four antacid tablets has a smaller volume. B. The two reactions produce the same amount of gas. C. The gas generated by two antacid tablets has a smaller volume. **my answer: C is that right?

terenzreignz (terenzreignz):

3 is correct, 4, no idea

OpenStudy (anonymous):

#5: A 1.0 L container holds a sample of hydrogen gas at 300 K and 101.5 kPa. If the pressure increases to 508 kPa and the volume remains constant, what will the temperature be? A. 103 K B. 605 K C. 1,501 K D. 901 K **my answer; C is that right?? and alrighty :)

terenzreignz (terenzreignz):

5 is correct

OpenStudy (anonymous):

kk :) thanks!

OpenStudy (anonymous):

kk :) thanks!

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