Question

simplify: 1/cot(x)-1/2sinxsecx

Answer 1

algebra is easier i you replace \(\cos(x)\) by \(a\) and \(\sin(x)\) by \(b\)

Answer 2

\[\frac{1}{\frac{a}{b}}-\frac{1}{2b\times \frac{1}{a}}\]

Answer 3

you get
\[\frac{b}{a}-\frac{a}{2b}\]

Answer 4

this isn't algebra it's trigonometry. I don't understand what you are doing.

Answer 5

then subtract, get \[\frac{2b^2-a^2}{2ab}\]

Answer 6

it is algebra, just with trig functions

Answer 7

is the question
\[\frac{1}{\cot(x)}-\frac{1}{2\sin(x)\sec(x)}\]?

Answer 8

yes, but i need to answer it using trig identies.

Answer 9

the reciprocal of cotangent is tangent, and the reciprocal of secant is cosine

Answer 10

so you can write
\[\tan(x)-\frac{\cos(x)}{2\sin(x)}\] if you like

Answer 11

is the answer tanx

Answer 12

no

Answer 13

you can subtract if you like

Answer 14

but the answer is not some simple trig function, at least not to the question you posted
there is a 2 in the denominator right?