Question

36x^2+85x+49=x

solve by factoring

Answer 1

36x^2 + 85x + 49 = x

Minus x from both sides of the equation

36x^2 + 84x + 49 = 0

Then multiply 36 by 49 and you get 1764

Find two numbers that multiply to be 1764 but add up to be 84

Answer 2

well the 1st and last terms are perfect squares

and if you subtract x from both sides the coefficient of the middle term changes to 84

which is double the product of the terms in a perfect square.

hope this helps..

as you are solving

\[36x^2 + 84x + 49 = 0\]

Answer 3

ps... don't worry about multiplying anything... what squared is 49, what squared isn 36x^2

Answer 4

im so lost

Answer 5

ok... this is a perfect square

\[(a + b)^2 = a^2 + 2ab + b^2\]

your question is

\[36x^2 + 84x + 49 = 0\]

can you find the values of a and b... in your equation...?

Answer 6

idk honestly

Answer 7

ok... what is \[\sqrt{36} =......... \sqrt{x^2}=..............\sqrt{49}=.............\]

Answer 8

any ideas yet..?

Answer 9

Hey @higherlearning r u even there??

Answer 10

Luk just follow wat u did in d previous sum.. Remember d way v did it? @higherlearning ??

Answer 11

okay let me help you out.. okay?? @higherlearning ?

Answer 12

36x^2+85x+49=x
now subtact x from both sides
36x^2+85x+49-x=x-x
so we get...
36x^2+84x+49=0
now we need to find 2 such factors of 36 X 44 which must add upto or must subtracted to obtain 1764 which is (36 X 44)...
now the factors are 42 and 42.. can u solve it now?

Answer 13

in case u dont and reply"i'm so lost"! lol!
here's how..
\[36x^2+42x+42x+49=0\]
\[6x(6x+7x)+7x(6x+7x)=0\]
\[(6x+7)(6x+7)=0\]
so its
\[6x+7=0 \] or \[6x=-7\] or \[x=-7\div 6\] okay??