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if y=2x-8 what is the minimum value of the product xy
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\[g(x)=x(2x-8)\implies g(x)=2x^2-8x\]
now maximize the function g(x)
i dont get why it turns into x(2x-8)
oh i get it nevermind
replace "y" :)
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i cant remember how to maximiz3
at a maxima or minima, the first derivative is "0" so, \(g'(x)=0\) and solve for "x"
I got 2 is that correct
yes.
thank yout
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now, check if g(x) is maxima or minima...
use the second derivative test to confirm g(x) has a maxima at x=2
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