Question

One number is nine more than a second number. Four times the first is 2 less than 6 times the second. Find the numbers.
Am I right?
(x+9)+y , (4x-2)+6y

Answer 1

in this case, you have to use a single variable.

Answer 2

so how do i rewrite it then?

Answer 3

the first number is nine more than the second;
(y+9) is the first number and then y is the second number

Answer 4

four times the first is two less than six times the second;
{4(y+9)}=6y-2

Answer 5

do u get it

Answer 6

i think so thank you so much!

Answer 7

what answer do u have

Answer 8

im working it one second..

Answer 9

19=y

Answer 10

but i need 2 values for each equation so why did i only have on outcome?

Answer 11

*number, not equation

Answer 12

4(y+9)=6y-2
4y+36=6y-2
10y=38
y=3.8
3.8 is the second number
but we read that the first number is 9 more than the second. so to get the first number, add 9 to the second number which is 3.8

Answer 13

first number = 3.8+9=12.8
second number = 3.8

Answer 14

why did you add 4y to 6y shouldnt you have subtracted?

Answer 15

sorry about that, i should have subtracted

Answer 16

first number= 19+9=28
second number=19

Answer 17

you were right

Answer 18

awsome okay thank you for struggling through that with me lol:)

Answer 19

u are welcome