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Verify: tanxcos(2x)=sin(2x)-tanx using trig indentites
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tanxcos(2x)=sinx/cosx.2cos^x-1=2cos^xsinx/cosx-sinx/cosx=sin(2x)-tanx
from yours, I have tanxcos(2x) +tan x = sin 2x = 2 sinx cos x factor out: tan x (cos 2x +1) = 2sinx cos x \[tanx = \frac{ 2sinxcosx }{ \cos2x +1 }= \frac{ 2sinx cosx }{ 2\cos^2 x}\] right side, cancel 2cos x you get \[tanx = \frac{ sinx }{ \cos x }\] Hope this helps
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