Consider the line that passes through the point (3, -2) and has a slope of 2. Part 1: Write the equation of this line using point-slope form. (2 points) Part 2: Using your equation from part 1, rewrite this equation in slope-intercept form. Make sure to show all of your work. (2 points) Part 3: Using your equation from part 2, rewrite this equation in standard form. Make sure to show all of your work. (2 points)
You can Smartly use Geometry to solve Questions like This. Now Try to use it, and let me Know if you are done.
Im not in geometry! im in algebra still!
what is point-slope form
\[y - y _{1} = m(x - x _{1})\]
ok, so just substitute the x and y from (3, -2) for y1 and x1, and the slope, 2, for m
y - (-2) = 2(x - 3)
so y + 2 = 2(x - 3)
do you know how to change it into slope-intercept form?
y + 2 = 2(x - 3) y + 2 = 2x - 6 - 2 - 2 y = 2x - 8
is this right?
yes :D
i just dont kno bout standard form
do you know what standard form is?
no...
Ax + By = C
and A can't be negative or a decimal
i dont kno how to solve that :(
y = 2x - 8 you have to subtract 2x -2x + y = -8 but A can't be negative, so you then have to divide everything by -1 2x - y = 8
equation is y=2x-8
so you divide 2x and 8 by -1?
point slope equation is y+2 = 2 (x-3)
you'd have to divide the whole equation by -1. and all that does is change the signs
y = 2 x-8 that is slope intercept form
standard form is y+2 = 2 (x-3)
so its -2x - y = -8
no it's 2x - y = 8
I just gave you all three forms that you need
ohhhh okay thank you :)
no problemo :]
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