x^(2)+18x+79=0 solve the quadratic equation by completing the square.
Do you know how to complete the square? Basically what you are trying to do is that you have to find something an expression like x + 2 or something, that when you square, contains that x^2 + 18x part in it. When it contains that, you can simply add or subtract whatever you need to in order to equalise the constant at the end. For example, if I have the function x^2 + 4x - 30 = 0 given to me and I have to complete the square, then I find something that when I square it, I get the "x^2 + 4x" part in it. So from what I know, squaring x + 2, will give me that x^2 + 4x in it. So it goes like this: (x + 2)^2 + k = x^2 + 4x - 30 x^2 + 4x + 4 + k = x^2 + 4x - 30 x^2 + 4x + 4 - 34 = x^2 + 4x - 30 (x + 2)^2 - 34 = x^2 + 4x - 30 So you see what I did there? I found something that when squared, contains the part of the equation that I want, but then to make the constant the same, I have to add a value k to the other side in order to make the constants the same on both sides. That's basically completing the square. @jmprz_793
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