Question is inside!! :D thanks :)
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answer choices: A. I only B. II only C. I and III only D. I and IV only **my answer; D. I and IV only is that correct? :D
It would have asymptotes at those values if those values are not part of their domain. So, which of these has no value, when \[\Large x = n\pi\]?
Pro-tip. Sine and Cosine have no asymptotes.
wait really?? so automatically sine and cosine will NEVER have asymptotes? and what do u mean by the question? ;/
Well, sine and cosine are defined no matter what x is... ie sin(x) and cos(x) always have values, for any real number x. So... remember, \[\tan x = \frac{\sin x}{\cos x}\]\[\cot x = \frac{\cos x}{\sin x}\]\[\sec x = \frac{1}{\cos x}\]\[\csc x = \frac1{\sin x}\]
So, each of these non-sine and non-cosine functions have denominators which COULD be zero, right?
i think so
So, between sin and cos, which one is zero, when x = n*pi?
can't neither of them be 0? because then it makes csc and sec undefined right? :/
Of course, it could be that neither of them are zero, but when is sine zero? When is cosine zero? In fact \[\huge \sin \ n\pi=0 \ \ \ \ \ \ for \ all \ n\in\mathbb{Z}\]
ohhh okay so what does that mean?
So, if \[\sin n\pi=0\]What does that mean for cot x and csc x?
Because cot x and csc x both have sin x in their denominators.
that they don't have asymptotes?
Means they DO have asymptotes :)
ohhhh i seee haha i got a bit confused for a sec.. lol so the final answer is D. I and IV only?? because of the above? ^^
Okay, I'm going to preempt you... The functions with asymptotes at \[\LARGE n\pi\]are the CO-functions, except cosine Means they include cot and csc. The functions with asymptotes at \[\LARGE \frac{\pi}{2}+n\pi\]are the non-CO-functions, except sine, means they include tan and sec.
okay.. so i just need to try and memorize that right?? what u just wrote? so is that right then? answer is D? :D csc and cot ?
That's right :) No need to memorise, if you can help it, but it sure helps ^.^
hahah oaky!! :D
thanksss :D
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