Question

Which function's graph has a period of 2?

(answer choices posted inside!)

Answer 1

answer choices A,B,C,D from top to bottom

***im not too sure, but i think it's either B or C...

what do y'all think? :)

Answer 2

If it's sin, cos, sec, csc, then, given that the thing inside the function is
\[\Large trig\left(bx+c\right)\]
Its period is
\[\huge \frac{2\pi}{b}\]


Note: You can replace trig by any of the following : sin, cos, sec, csc.

Answer 3

okay, so sin(bx+c)
cos(bx+c)
sec(bx+c)
csc(bx+c)
??

Answer 4

Yeah, so, you see that b? (b is whatever coefficient x has)
2pi/b gives you the period.

Answer 5

and with what u put above, i'm thinking the answer is C. y= 3cos pi x since you have the pi in it... and the pi is after the 3cos part... is that right?? :) is it C? :D because of that?

Answer 6

C is
y = -4sin 2x
:P

Answer 7

ohh sorry!! lol i meant B.. is the answer B then?? :)

Answer 8

Yeah, it's B, since (T is period)
\[\huge T=\frac{2\pi}{\pi}=2\]

Answer 9

aweosme! :D yayy :D thanks!!!