If z varies directly as y^(2) and inversely as x, which of the following must be constant?
A. xy^(2)z
B. y^(2)z / x
C. xz/y^(2)
D. z/xy^(2)
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OpenStudy (shubhamsrg):
just the same ques as your last one.
OpenStudy (anonymous):
ummm...
Parth (parthkohli):
The product of the things that vary inversely is always constant...
OpenStudy (shubhamsrg):
are you changing pics ever other second? or some kinda screensaver you have put on? -_-
OpenStudy (shubhamsrg):
every*
@kryton1212
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OpenStudy (anonymous):
@shubhamsrg haha i have nothing to do xD
Parth (parthkohli):
@kryton1212 So is the hint I gave you fine?
OpenStudy (anonymous):
@ParthKohli is it always true?
Parth (parthkohli):
@kryton1212 Yup.
OpenStudy (anonymous):
@ParthKohli thanks:)
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Parth (parthkohli):
So what is the product of the things that vary inversely here?
OpenStudy (kropot72):
\[z=\frac{ky ^{2}}{x}\]
where k is a constant of proportionality. Solve for k to find the solution.
OpenStudy (anonymous):
wait a minute, let me check it again
Parth (parthkohli):
Grr, I read the question wrong.
OpenStudy (anonymous):
...
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Parth (parthkohli):
If you have a direct proportion, then the division is constant.
If you have an inverse proportion, then the product is constant.
So, in this question, ...
Parth (parthkohli):
Am I confusing you?
OpenStudy (anonymous):
nope, thank you very much, you have given me a very big hint.
Parth (parthkohli):
I hope you understood. If so, you're welcome!
OpenStudy (anonymous):
is it B?
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Parth (parthkohli):
Umm, no.
Parth (parthkohli):
You could take a look at kropot's post.
OpenStudy (anonymous):
C?
OpenStudy (anonymous):
@ParthKohli ummm..
OpenStudy (kropot72):
Did you try to find k by rearranging
\[z=\frac{ky ^{2}}{x}\]
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