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Mathematics 16 Online
OpenStudy (anonymous):

If z varies directly as y^(2) and inversely as x, which of the following must be constant? A. xy^(2)z B. y^(2)z / x C. xz/y^(2) D. z/xy^(2)

OpenStudy (shubhamsrg):

just the same ques as your last one.

OpenStudy (anonymous):

ummm...

Parth (parthkohli):

The product of the things that vary inversely is always constant...

OpenStudy (shubhamsrg):

are you changing pics ever other second? or some kinda screensaver you have put on? -_-

OpenStudy (shubhamsrg):

every* @kryton1212

OpenStudy (anonymous):

@shubhamsrg haha i have nothing to do xD

Parth (parthkohli):

@kryton1212 So is the hint I gave you fine?

OpenStudy (anonymous):

@ParthKohli is it always true?

Parth (parthkohli):

@kryton1212 Yup.

OpenStudy (anonymous):

@ParthKohli thanks:)

Parth (parthkohli):

So what is the product of the things that vary inversely here?

OpenStudy (kropot72):

\[z=\frac{ky ^{2}}{x}\] where k is a constant of proportionality. Solve for k to find the solution.

OpenStudy (anonymous):

wait a minute, let me check it again

Parth (parthkohli):

Grr, I read the question wrong.

OpenStudy (anonymous):

...

Parth (parthkohli):

If you have a direct proportion, then the division is constant. If you have an inverse proportion, then the product is constant. So, in this question, ...

Parth (parthkohli):

Am I confusing you?

OpenStudy (anonymous):

nope, thank you very much, you have given me a very big hint.

Parth (parthkohli):

I hope you understood. If so, you're welcome!

OpenStudy (anonymous):

is it B?

Parth (parthkohli):

Umm, no.

Parth (parthkohli):

You could take a look at kropot's post.

OpenStudy (anonymous):

C?

OpenStudy (anonymous):

@ParthKohli ummm..

OpenStudy (kropot72):

Did you try to find k by rearranging \[z=\frac{ky ^{2}}{x}\]

Parth (parthkohli):

@kryton1212 C is correct :-)

OpenStudy (anonymous):

thanks

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