Question

Please help!!!

Answer 1

@RH we can write
\[x ^{-1} = \frac{ 1 }{ x }\]
use this concept and solve the given expression

Answer 2

@niksva 1/2c x(times) d + 1/2d x c

Answer 3

Is this correct?

Answer 4

no the correct expression would be
\[\frac{ 2d }{ c } +\frac{ 2c }{ d }\]

Answer 5

@niksva Oh ok :( do I need to simplify it more?

Answer 6

take the LCM in third step
and then take 2 out in fourth step

Answer 7

2(d/c + c/d) @niksva

Answer 8

is this correct?

Answer 9

yeah
now take the LCM
for example = if u want to add \[\frac{ 1 }{ 2 } + \frac{ 1 }{ 3 }\]
LCM of 2 and 3 is 6
therefore, \[\frac{ 1 }{ 2 } +\frac{ 1 }{ 3 } = \frac{ 3+2 }{ 6 }\]
= \[\frac{ 5 }{ 6 }\]

Answer 10

I am not sure how I would do that :( @niksva

Answer 11

for 2(d/c + c/d) how would I do that?

Answer 12

\[2(\frac{ d }{ c }+ \frac{ c }{ d } ) = 2 (\frac{ d*d+c*c }{ cd }) = 2(\frac{ d^2+c^2 }{cd })\]

Answer 13

Thank you so much!!!!

Answer 14

There is no simplifying anymore, right? @niksva

Answer 15

yah

Answer 16

THANKS!