Mathematics
6 Online
OpenStudy (anonymous):
HELP PLEASE!
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OpenStudy (anonymous):
OpenStudy (anonymous):
Would the top part be 1/x + 2/x
OpenStudy (anonymous):
and the bottom part 1 + 1/x
OpenStudy (anonymous):
top part would be 1/x + 2/x^2
bottom part is right
OpenStudy (anonymous):
@niksva Thank you! Is there more simplifying to the problem? or is that it?
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OpenStudy (anonymous):
yeah u have to do the simplification more
first take the LCM in numerator and denominator
and atleast show what you r getting
OpenStudy (anonymous):
Ok. Would the top part be x+2/x^2 @niksva
OpenStudy (anonymous):
and the bottom part x+1/x
OpenStudy (anonymous):
correct
now cancel the like terms
OpenStudy (anonymous):
I am not sure how to do that? :( @niksva
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OpenStudy (anonymous):
can we write
\[\frac{ x+2 }{ x^2 } * \frac{ x }{ 1+x }\] ?
OpenStudy (anonymous):
yes!!!
OpenStudy (anonymous):
now what r u going to get?
OpenStudy (anonymous):
hmm maybe factor it? :(
OpenStudy (anonymous):
I don't know :( @niksva
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OpenStudy (anonymous):
can we write
\[\frac{ x+2 }{ (x*x) } * \frac{ x }{ 1+x }\] ?
OpenStudy (anonymous):
cancel the like terms
OpenStudy (anonymous):
the x's get canceled right? and then we write x+2/ x ∗ 1 +x
OpenStudy (anonymous):
Is it correct? @niksva
OpenStudy (anonymous):
yeah it is correct
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OpenStudy (anonymous):
you could also achieve the result by multiplying top and bottom by \(x^2\) as a first step
OpenStudy (anonymous):
@niksva THANKYOU!
OpenStudy (anonymous):
@niksva that is the end of the problem, right?
OpenStudy (anonymous):
yup