Ask your own question, for FREE!
Mathematics 6 Online
OpenStudy (anonymous):

HELP PLEASE!

OpenStudy (anonymous):

OpenStudy (anonymous):

Would the top part be 1/x + 2/x

OpenStudy (anonymous):

and the bottom part 1 + 1/x

OpenStudy (anonymous):

top part would be 1/x + 2/x^2 bottom part is right

OpenStudy (anonymous):

@niksva Thank you! Is there more simplifying to the problem? or is that it?

OpenStudy (anonymous):

yeah u have to do the simplification more first take the LCM in numerator and denominator and atleast show what you r getting

OpenStudy (anonymous):

Ok. Would the top part be x+2/x^2 @niksva

OpenStudy (anonymous):

and the bottom part x+1/x

OpenStudy (anonymous):

correct now cancel the like terms

OpenStudy (anonymous):

I am not sure how to do that? :( @niksva

OpenStudy (anonymous):

can we write \[\frac{ x+2 }{ x^2 } * \frac{ x }{ 1+x }\] ?

OpenStudy (anonymous):

yes!!!

OpenStudy (anonymous):

now what r u going to get?

OpenStudy (anonymous):

hmm maybe factor it? :(

OpenStudy (anonymous):

I don't know :( @niksva

OpenStudy (anonymous):

can we write \[\frac{ x+2 }{ (x*x) } * \frac{ x }{ 1+x }\] ?

OpenStudy (anonymous):

cancel the like terms

OpenStudy (anonymous):

the x's get canceled right? and then we write x+2/ x ∗ 1 +x

OpenStudy (anonymous):

Is it correct? @niksva

OpenStudy (anonymous):

yeah it is correct

OpenStudy (anonymous):

you could also achieve the result by multiplying top and bottom by \(x^2\) as a first step

OpenStudy (anonymous):

@niksva THANKYOU!

OpenStudy (anonymous):

@niksva that is the end of the problem, right?

OpenStudy (anonymous):

yup

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!