Question

1. Simplify: (2x + 9)(4x2 + 2x - 12)

Answer 1

Distribution :)
Just do it :>
a(p+q+r) = ap + aq + ar

Answer 2

oh! and that 4x2 is actually supposed to be a 4x^2

Answer 3

But how would i be able to use distribution on this problem when there is not a number on the beginning of the outside of theses expressions?

Answer 4

Don't worry, I know :)
I got ya :3
so... distribute


(2x + 9)(4x² + 2x - 12)
=
4x²(2x+9) + 2x(2x+9) - 12(2x+9)

It may not be A number, but it can still be distributed, as a whole :)

Answer 5

Oh okay! So I would solve the same way I would solve a regular distribution problem?

Answer 6

Yeah :)
But now, you have to distribute again :)

Answer 7

hold on I have to do this on paper! lol I am really slow at math!

Answer 8

Take your time :3

Answer 9

@PeterPan would you also multiply 4x^2 by the +9?

Answer 10

Of course :)
It's a distribution just like any other ^.^

Answer 11

Oh okay! So @PeterPan when you multiply the 4x twice you get 16 or would you just leave that 4x^2?

Answer 12

Let's do that first part :)
4x²(2x+9)
We multiply 4x² to 2x, we get...8x³
We multiply 4x² to 9, we get 36x²
So...
4x²(2x+9) = 8x³ + 36x²

Any questions?
Do the rest ^.^

Answer 13

well isnt 4x times 4x 16? because dont you have to multiply it by the same number twice not by 2? because thats how my teacher explained it.

Answer 14

Of course 4 x 4 = 16
But why would this interest us? There is no instance of 4x4 in the problem :)

Answer 15

yeah, but i meant that since their 4x to the power of 2 wouldnt that mean it would be 4x multiplied by 4x?

Answer 16

AHH
\[\huge 4x^2=4\cdot x\cdot x \ne 4x\cdot 4x\]
\[\huge 4x\cdot 4x=(4x)^2\ne4x^2\]

Answer 17

Would the answer be 44x^5?

Answer 18

Oh okay!

Answer 19

@PeterPan would the answer be 44x^5?

Answer 20

No...
I told you to distribute
4x²(2x + 9)
what do you get?

Answer 21

well @PeterPan