Systems of Linear Inequalities Determine whether the ordered pair is a solution of the given system. A) (2.12); y>2x +4 y<3x +7 Solve each system of inequalities by graphing. B) y < 2x +4 -3x - 2y (greater than or equal too) 6
Also remember to tag? @PeterPan ^.^ @TheKylieeM There's a way to determine A... just replace x with 2, and replace y with 12.
Okay @PeterPan
So, in both inequalities, y>2x+4 y<3x+7 Replace x with 2 and y with 12 See if it fits :)
So @PeterPan the first one would be y>2(2)+4? then multiply the 2(2)?
Don't forget to replace y with 12 :)
Yes I know I just did that one which I got y<36 + 7 so my answer for both would be y>8 y<43
@PeterPan right?
y<43 ? How did you get? >.>
I added the 7 and the 36 I got from y<3(12) + 7
because 3(12) is 36... i think.
but that was an x :/ Why did you replace it with 12? I said replace x with 2 replace y with 12 Careful next time, okay? ^.^
Oh! Okay! Hold on! Again! lol
Okay @PeterPan now I got for answers: 12>8 && 12 <10 so the first one should be the solution for the given set.
12 < 10 ? Redo :)
yes. because 3(2) is 6 and 6 + 4 = 10
oh wait! I remember now!
But it was y<3x +7 not y<3x +2
oh I accidently put 4! instead of 7!
so then is would be 12<13 @PeterPan
Yeah, much better :) So... is 12 > 8 true?
Yes that is true! So yes the ordered pair is a solution for equation A
YES it is a solution for the FIRST INEQUALITY, but is it a solution for the second inequality? Is 12 < 13 true?
Yes it is because 13 is greater than 12! :)
and 12 is less than 13! :)
Then, it's settled. (2,12) is a solution of the system :)
Whoo hoo! Next question! :D
hmmm... this is gonna be a tricky one :) Can you graph lines?
Yes I can but I did look at this equation and I am VERY confused on how to graph something like this....
Yes, don't worry :) First, pretend they're lines, and graph them... y = 2x +4 -3x - 2y = 6
I'm still confused on how to graph lines like that... :|
@PeterPan
Hmm... first put them in this form: y = mx + b
and how do I do that exactly? Also what do each letter stand for?
@PeterPan keep forgetting to tag you! ooops lol
Only tag me once. What I want you to do is rearrange the equation so that y stands alone on one side of the equation :)
like 2y - (-3x) (greater than or equal too) 6?
and y is already standing alone on the first equation
forget that they are inqualities, for now. -3x - 2y = 6
okay but could it also be like the one I just gave but 2y - (-3x) = 6?
No... because 2y - (-3x) = 2y+3x which isn't the same as -2y - 3x
but you just flip the inequality sign right? dont you have to do that when theres a negative?
Yeah, sure, but you sure failed to negate the right side (6)
negate?
make negative.
Oh! ...................................
so then how can i be able to make the y stand alone? I am really confused... o.0
Hang on...
Alright
Here, an example :) \[\Large ax + by = c\]to isolate y, we bring all those without y to the right-side \[\Large by=-ax+c\]Then divide everything by b, the coefficient of y... \[\Large y = \frac{-ax+c}{b}\]That's how to isolate y :)
Okay so to get why by its self I have to divide -3x - 2 by 6??
y***
No...
grrrrrrrrrrrrr......................
Let's do it slowly :) \[-3x-2y=6\]Let's bring x to the right side \[-2y=3x+6\]
Oh! I thought that the 2 had to be on the same side as the 3
Not really, as long as you can get the y alone on one side, it should work :)
okay so next step?
Well, on the left side, it still says -2y, so we better divide everything by -2, to get rid of that coefficient, we get \[\Large y = \frac{3x-6}{-2}\]And there you go, y is alone on one side :)
Oh! okay! so then?
Well, simplify... \[\Large y = -\frac32x+3\]
I'm going to graph this line, and you do the other, okay?
okay
|dw:1364659472280:dw|The coordinate system :)
okay
brb!
The way to graph a line is to get its intercepts. Its y-intercepts and x-intercepts. Its x-intercept is obtained by letting y = 0, indeed, you can check this, if y = 0, then x = 2 So its x-intercept is the point (2,0)|dw:1364659606563:dw|
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