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Chemistry 9 Online
OpenStudy (anonymous):

Analysis of a gas indicated that 46.2 % of its mass was carbon and 53.8% of the mass was nitrogen.

OpenStudy (anonymous):

At 25oC and 751 torr, 1.05 g of the gas occupies 0.500 L. What is the molecular formula for the gas?

OpenStudy (anonymous):

Does it matter if this is an ideal gass because I would like to use PV = nRT = ideal gass law

OpenStudy (goformit100):

|dw:1364660898982:dw|

OpenStudy (anonymous):

using this equation i got moles = 0.020194 moles

OpenStudy (anonymous):

@Callisto

OpenStudy (anonymous):

@Yahoo!

OpenStudy (anonymous):

@.Sam.

OpenStudy (anonymous):

CN or C2N2......?

OpenStudy (anonymous):

any ideas?

sam (.sam.):

yes

sam (.sam.):

We can get the number of moles of the total gas with PV=nRT, see picture below, we get 0.020195 mol of gas

sam (.sam.):

OpenStudy (anonymous):

yes I got that

OpenStudy (anonymous):

but what I need is how to get the molecular formula because I only have percent by mass

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