Question

Use the table from Lesson 9, not your calculator or computer, to find tan(π/6).
b. √3
c. 1/√3
d. √2

Answer 1

I'm not sure how to do this.

Answer 2

Remember that tan = sin/cos

Answer 3

For every ordered pair on the unit circle, the cosine (cos) is the horizontal (x) component, and the sine (sin) is the vertical (y) component.

Answer 4

qpHalcy0n is right, substitute to the tan=sin/cos

Answer 5

sin(pi/6)/cos(pi/6)

Answer 6

I got (sqr3)/3

Answer 7

\[\frac{ \frac{ 1 }{ 2 } }{ \frac{ \sqrt{3} }{ 2 } }\]

Answer 8

then it is 1/root(3)

Answer 9

How?

Answer 10

oops, you are right sorry

Answer 11

They don't give that choice, though.

Answer 12

in my calculation it is 1/root3 but in calculator it is root(3) over 3

Answer 13

see above

Answer 14

Oh, okay, I see. Thank you.

Answer 15

sin(pi/6)=1/2
cos(pi/6)=root(3)/2

Answer 16

Can you help with one other?

Answer 17

yes

Answer 18

Find cot(π/3).

Answer 19

cot=cos/sin

Answer 20

so the same method

Answer 21

\[\Large \frac{\sqrt{3}}{3}\] and \[\Large \frac{1}{\sqrt{3}}\] are the same, here's why



\[\Large \frac{\sqrt{3}}{3} = \frac{\sqrt{3}*\sqrt{3}}{3\sqrt{3}}\]


\[\Large \frac{\sqrt{3}}{3} = \frac{\sqrt{3*3}}{3\sqrt{3}}\]


\[\Large \frac{\sqrt{3}}{3} = \frac{\sqrt{9}}{3\sqrt{3}}\]


\[\Large \frac{\sqrt{3}}{3} = \frac{3}{3\sqrt{3}}\]


\[\Large \frac{\sqrt{3}}{3} = \frac{1}{\sqrt{3}}\]

Answer 22

Okay, that makes sense. Thank you both!

Answer 23

yw