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OpenStudy (anonymous):
How many grams of carbon are present in 45.0 g of CCl4?
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OpenStudy (anoop27):
CCl4=(12+35.5*4)gms=(12+142)gm=154gms 154 gm of CCl4 contains 12 gm of Carbon 1gm of CCl4 contains 12/154 gm of Carbon 45 gm of CCl4 contains (12*45)/154 gm of Carbon so your Answer is (12*45)/154 gms
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