Question

I have tha answer can someone please just check me...
Find the derivative of
p(x)=cos(ln(3x-1))

Answer 1

you got what?

Answer 2

I got \[\frac{ 3\sin(\ln(3x-1)) }{ 3x-1 }\]

Answer 3

again you lost a negative sign somewhere, the derivative of cosine is negative sine

Answer 4

p(x) = cos(ln(3x-1))


p ' (x) = d/dx[ cos(ln(3x-1)) ]


p ' (x) = -sin(ln(3x-1))*d/dx[ln(3x-1)]


p ' (x) = -sin(ln(3x-1))/(3x-1)*d/dx[3x-1]


p ' (x) = -sin(ln(3x-1))/(3x-1)*3


p ' (x) = -3sin(ln(3x-1))/(3x-1)

Answer 5

other than that, everything else is correct

Answer 6

ok so its just a negative on the top then

Answer 7

yep

Answer 8

thanks

Answer 9

np