Question

What is the equation in standard form which passss through (3, -6) and (-2,-1)

Answer 1

When two points are given like \((x_1, y_1)\) and \((x_2, y_2)\), then use two point slope form:

\[\large \color{blue}{\frac{y - y_1}{y_2 - y_1} = \frac{x - x_1}{x_2 - x_1}}\]

Answer 2

Which gives 1/-7

Answer 3

Here :

\(x_1 = 3\), \(x_2 = -2\)
\(y_1 = -6\). \(y_2 = -1\)

Plug in the values and find the equation..

Answer 4

You cannot substitute for x and y as they are just arbitrary constants.. Your final answer will consist of x and y..

Answer 5

Huh?

Answer 6

Can you solve this:

\[\frac{y + 6}{-1 + 6} = \frac{x - 3}{-2-3}\]

Cross Multiply and solve..

Answer 7

@londoneaves22

The slope of the line determined by the points (3, -6) and (-2,-1) is -1.

Using the point-slope general form of a line:

y - y1 = m(x - x1) where m represents slope and (x1,y1) is a point on the line.
I chose (3, -6) which is one of the two points on the line.

y - (-6) = (-1)* (x - 3)
y + 6 = -1*x + 3

y = -1*x - 3 --> This is the equation of the line in slope-intercept form.

What is the equation in standard form?
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So, you have some work to do to get the equation in standard form.

The Standard Form for a linear equation in two variables, x and y, is usually given as
Ax + By = C
where, if at all possible, A, B, and C are integers, and A is non-negative, and, A, B, and C have no common factors other than 1.

y = -1*x - 3 needs to be placed in this form: Ax + By = C.