A company estimates that it will sell N(x) hair dryers after spending $x thousand on advertising as given by: N(x)=-0.25x^4+13x^3-180x^2+10,000 for 15<=x<=24 When is the rate of change of sales increasing, decreasing?(Hint: Find N'(x) which is the rate of change, then find N"(x) to check when N'(x) increasing or decreasing)
If N(x) = -0.25x^4+13x^3-180x^2+10000 then N ' (x) = ???
-1x^3+39x^2-180
good
now what is N '' (x)
-3x^2+78x
very nice
Im almost a pro haha
you're definitely a pro
Now we need to find the roots of N '' (x) = -3x^2+78x N '' (x) = -3x^2+78x 0 = -3x^2+78x -3x^2+78x = 0 -3(x-26) = 0 x - 26 = 0 x = 26 So x = 26 is a possible point of inflection
If x = 25 (a value to the left of x = 26), then N '' (x) = -3x^2+78x N '' (25) = -3(25)^2+78(25) N '' (25) = 75 This tells us that the rate of change is increasing on the interval (-infinity, 26)
If x = 27, then N '' (x) = -3x^2+78x N '' (27) = -3(27)^2+78(27) N '' (27) = -81 which means that the rate of change is now decreasing on the interval (26, infinity)
if we restrict the interval to 15 <= x <= 24 (just saw this part), then the rate of change of the sales is increasing because 15 <= x <= 24 is definitely in the interval (-infinity, 26)
okay, so the increasing interval is set
since the derivative is increasing throughout the interval 15 <= x <= 24, there are no intervals where it is decreasing
so I would say NA or none or something like that
oh wow that was a lot easier than I thought!
yeah not too bad
this is only true because 15 <= x <= 24 is all below 26 where everything is increasing if you stretched it from 15 <= x <= 24 to 15 <= x <= 34, then it would be a different story
I want to know why n'(x) isn't -1x^3+39x^2-360x?
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