Question

Find domain(s).

Answer 1

\[\LARGE y=\frac{x^2-5x+4}{x^2-3x+2}\]

Answer 2

\[\LARGE y=\frac{\cancel{(x-1)}(x-4)}{\cancel{(x-1)}(x-2)}\]
It is undefined at 4,2
So it should be
R-{4,2} ?

Answer 3

Why is this rational function undefined at x = 4? Just wondering.

I think you meant to put another value of x instead of 4.

The domain is the set of acceptable values of x.

Answer 4

Oops,R-{1,2}?

Answer 5

The set of Reals excluding x = 1 and 2. Yes, I agree.

Answer 6

or just R-{2}?

Answer 7

since x-1 factor cancels out

Answer 8

The x -1 divides out under the condition that x is not equal to one.
So, R-{1,2} is your domain.
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If you draw the graph of y = (x² - 1) / (x - 1), the graph will be a line with a hole in it at the point (1, 2).

Answer 9

I have another doubt.

Answer 10

What is it?

Answer 11

\[\LARGE \sqrt{\log_{10} \frac{3-x}{x}}\]

Answer 12

isn't it simply x<3 that is..
{2,1}

Answer 13

My computer is not loading the math symbols so I am unsure what you wrote.

Processing math: 0% --> Lower left of my screen

Answer 14

square root of log base 10 fraction(x-3) upon x.

Answer 15

It can only accept 2,1 if im correct,ofc im not.