why is there a small potential in the completely connected circuit even when the input potential is kept zero(using rheostat)?

Question

goformit100 · Answer

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shane_b · Answer

If you're using a rheostat to block voltage some voltage will "leak" by.  Rheostats don't have an infinite amount of resistance.

anonymous · Answer

when you try to maintain the potential to zero, using a rheostat, you are effectively just getting your dividing the 'real' voltage between a very large resistance and a relatively small resistance. The voltage over the smaller resistance gives you your required apparant zero voltage. but the small resistance will always have some magnitude, however small it may be. Thats where the tiny ghost  voltage comes from

anonymous · Answer

thanks you all. but now i don't know what that u=0.5kx2 is doing up there by goformit100

shane_b · Answer

Join the club :)  I'm not sure why he posted the elastic PE formula...

anonymous · Answer

hey if you've ever done some experiment of optical fiber can you tell me why we get a linearity in the graph and what does it represent??? |dw:1364936348971:dw|