Question

ok,
need to write 81^-3/4 in radical notation.

i came up with 4 OVER 3(sqroot)81

and then I have to simplify that to a fraction or integer

@satellite73

How'd I do?

Answer 1

you have an exponent with three feature
a) a denominator of 4
b) a numerator of 3
c) a minus sign

they mean in turn

a) the fourth root
b) the cube
c) the reciprocal

Answer 2

so
\[81^{-\frac{3}{4}}\] can be written as
\[\frac{1}{\sqrt[4]{81^3}}\]

Answer 3

and evaluated via
\[\sqrt[4]{81}=3\]
\[3^3=27\]
\[\frac{1}{27}\] as your final answer

Answer 4

I forgot the 1! lol i had it half right... haha. a little mixed up ..but i'm understanding it. thak you :)

Answer 5

yw