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Mathematics 10 Online
OpenStudy (anonymous):

please help with complete matric

OpenStudy (anonymous):

let \[\left( X;d \right)\] be a matric space and \[C_{b}\]\[\left( X,R \right)\] denote the set of all continuous bounded real valued functions defined on X, equipped with the uniform metric. \[ d\left( f,g \right)=sup{ \left| f \left( x \right)-g \left( x \right) \right|: xinX }\] Show that \[C_{b}\]\[\left( X,R \right)\] is a complete matric space

OpenStudy (anonymous):

please help @ timo86m

OpenStudy (anonymous):

sorry idk this one :(

OpenStudy (anonymous):

@timo86m

OpenStudy (anonymous):

@Callisto ,@Chlorophyll ,@charliem07 please help

OpenStudy (anonymous):

@Chlorophyll

OpenStudy (anonymous):

@charliem07

OpenStudy (anonymous):

sorry i dont know

OpenStudy (anonymous):

ok cool

OpenStudy (anonymous):

@Chlorophyll please help

OpenStudy (anonymous):

@hartnn please help

OpenStudy (anonymous):

@UnkleRhaukus please help

OpenStudy (unklerhaukus):

@JamesJ, @experimentX, @eliassaab, @nbouscal, @beketso

OpenStudy (anonymous):

@TuringTest please help

OpenStudy (turingtest):

@KingGeorge

OpenStudy (turingtest):

btw for advanced questions you may have better luck here http://math.stackexchange.com/

OpenStudy (anonymous):

k thanx

OpenStudy (anonymous):

your job is showing it is "complete" is to show that if \(f_n\to f\) then \(f\in C_b\)

OpenStudy (anonymous):

that is, if a sequence of continuous functions converges to some function using the sup metric, then the limit function is continuous also

OpenStudy (anonymous):

this should work because the metric is the supremum over all \(x\)

OpenStudy (anonymous):

the general idea is that under the sup metric, the convergence is uniform, and the uniform limit of a sequence of continuous functions is uniform gotta run, but if you google what i wrote i bet you will find a worked out solution

OpenStudy (anonymous):

do i have to let the sequence to be a cauchy sequence first?

OpenStudy (anonymous):

actually what i meant is the uniform limit of a sequence of continuous functions is CONTINUOUS

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

my problem we are given f and g and they are different how am i going to proof them simultaneously

OpenStudy (anonymous):

@Mertsj

OpenStudy (anonymous):

@ash2326

OpenStudy (anonymous):

@walters

OpenStudy (anonymous):

@phi please help me

OpenStudy (phi):

I assume you mean "metric space" ? But I tend more to applied math problems. i.e. not this kind of question.

OpenStudy (anonymous):

ok cool

OpenStudy (anonymous):

can u fynd me someone who can do it

OpenStudy (anonymous):

@dmezzullo please help

OpenStudy (anonymous):

@mathslover please help

mathslover (mathslover):

Sorry, am not good at this topic.

OpenStudy (anonymous):

ok can you search for me where i can find something related to ths?

mathslover (mathslover):

Yes! I am best at that field :)

OpenStudy (anonymous):

lol i will be glad

mathslover (mathslover):

https://www.youtube.com/watch?v=04pvLCDbq1c ^ a video tutorial

OpenStudy (anonymous):

eish they blocked youtube here at school

mathslover (mathslover):

oh forgot this : http://www-history.mcs.st-and.ac.uk/~john/analysis/Lectures/L15.html

OpenStudy (anonymous):

ok thanx

mathslover (mathslover):

Have a look at the links and let me know whether they helped or not.

OpenStudy (anonymous):

ok i will

OpenStudy (anonymous):

@mathslover they are not helping

mathslover (mathslover):

http://www.wiziq.com/tutorial/88701-Problems-in-Metric-Spaces-1 Check it out

OpenStudy (anonymous):

@Luis_Rivera please help

OpenStudy (anonymous):

@Agent_Sniffles

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