Mathematics
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OpenStudy (anonymous):
Can someone please explain how to solve 45-45-90 angles, and the theorem used to solve it.
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OpenStudy (anonymous):
45-45-90 triangles... in other words, isosceles right triangles :)
OpenStudy (anonymous):
|dw:1364749080972:dw|
OpenStudy (anonymous):
So, you're usually given one of the sides and asked to determine the rest, right? ^_^
OpenStudy (anonymous):
Yes :) I know the hypotenuse equals 2 squared times the leg, right?
OpenStudy (anonymous):
You mean square root of 2, right? :/
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OpenStudy (anonymous):
|dw:1364749284280:dw|
OpenStudy (anonymous):
Um yes :s I'm confused with all of it really O_o I've been trying to understand it for the past hour
OpenStudy (anonymous):
Well, you have a problem we can work on?
OpenStudy (anonymous):
Yeah, here's one :)
OpenStudy (anonymous):
f=√ ̅2 times 44 would be the first step? O_o
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jhonyy9 (jhonyy9):
so you need calculi the side p ?
OpenStudy (anonymous):
yes ._. sorry I meant P* earlier,
jhonyy9 (jhonyy9):
than sin 45 = p/44
jhonyy9 (jhonyy9):
us this
jhonyy9 (jhonyy9):
hope you know the value of sin 45 ,yes ?
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jhonyy9 (jhonyy9):
come on please cooperat anything
OpenStudy (anonymous):
Um 0.7071?
jhonyy9 (jhonyy9):
write every calculi please here step by step
jhonyy9 (jhonyy9):
but in the calculi for sin and cos 45 we us sqrt2 / 2
OpenStudy (anonymous):
yeah sorry I'm not following you O.o
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jhonyy9 (jhonyy9):
so than
sin 45 = p/44
sqrt2 /2 = p/44
p= 44sqrt2/2 = 22sqrt2
p=22sqrt2
jhonyy9 (jhonyy9):
ok ?
jhonyy9 (jhonyy9):
yw
good luck
bye
OpenStudy (anonymous):
Well I'm sure I'll understand it sometime. :) Thanks for your help though
jhonyy9 (jhonyy9):
yw
was my pleasure