Question

Problem posted.

Answer 1

\[E(t)=\frac{ 13500 }{ t+1 }\]
\[L(t)=\frac{ 4500t+250 }{ t+1}\]

Answer 2

At what time does the lake reach its maximum volume? What is the maximum volume of the lake?

Answer 3

E(t) represents rate at which water entered the lake.
L(t) represents rate at which water leaves the lake.

Answer 4

Since E(t) and L(t) are rates, I said E(t) - L(t) = 0

Answer 5

Thus E(t) = L(t) when t=2.944

Answer 6

amount of water at any instant in the lake = E(t)-L(t) =
now differentiate the above and set it equal to zero and find t