"5 dm^3 of SO2 reacts with 5dm^3 of Oxygen (02). What is the volume of the product, SO3?" Please help!!!! test after tomorrow...
you have to write an equation and balance it
then if you're given mass you have to convert it to moles... but in cases like these, where you assume gas ideality, 1 mole = 22.414 L so the number of moles is proportional to the volume of gas.
but they're not gases
they are gases
Only 02 is a gas
so2 and so3 are solids
nope, they would give you a mass if they were solids. if they were liquids, they would give you a concentration along with the volume
5 dm^3 of a solid is a huge amount
oh
so this is what i did so far, tell me if I'm doing it right or not:
I have 2So2 + O2 ---> 2SO3
and then we have to find limiting reagent?
SO_2 is limiting reactant
yep, so far so good
So the SO2 would give us 0.22 moles of SO3
V = 22.4 * 0.22
which equals 4.9
let me check in the answers if this is right did i do it right?
you forgot to use the stoichiometric coefficients
I didn't need to multiply it though
because its 2SO_2 + O2 ---> 2SO3
2 * 1 = 2
oh sorry you're right
ok i checked the answers it says 5 which is basically 4.9 rounded thanks a lot for helping me
no prob ! sorry about the confusion I'm doing too many things at once
no problem
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