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find the sum to the required number of terms for the geometric series 243+81+27+... to 7 terms i know the formula is s=b1*(1-q^n)/(1-q) but every time i plug it in i get 1093/3 can someone else tell me how to plug it inn please
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b1=243
q=1/3
so find it
n=7
\[243 \times \dfrac{1 - \dfrac{1}{3^7}}{1 - \dfrac{1}{3}}\]
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ParthKohli just gave you the explicit answer, where did you mistake
ok i did that and i still got 1093/3
That's weird.
You can just calculate \(243 + 81 + 27 + 9 + 3 + 1 + \dfrac{1}{3}\)
that's correct by the way) xDD
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what did you get when u simplified the equation
lol
yeah, that is correct.
1093/3 is correct?
yes, that's correct) xD
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oh ok thank youu
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