How can i get the net ionic equation for Na2CO3 + 2HCl = CO2 + H2O + 2NaCl

Question

anonymous · Answer

First you need to find the ionic equation.
Separate all the reactants and products into their respective ions.

Then, cancel out all spectators and you are left with the net ionic equation.

anonymous · Answer

would it be Na2CO3 + 2H+ 2Cl -> H2O + CO2 + 2Na +2Cl?

Na2CO3 + 2H -> H2O + CO2 + 2Na

anonymous · Answer

@dimensionx

anonymous · Answer

Be sure to include positive and negative charges, you also need to separate the Na2CO3 into ions.

thomaster · Answer

Na2CO3 would split up in 2Na+ and CO3 2-
So you can cancel out 2Na+ too
That would leave 2H+(aq) + CO3-2(aq) --> H2O(l) + CO2(g)

anonymous · Answer

ohhhhh so i split the first one too? thanks

thomaster · Answer

Also don't forget the physical state symbols (g) (s) (l) (aq) and (cr) :P