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Chemistry 10 Online
OpenStudy (anonymous):

How can i get the net ionic equation for Na2CO3 + 2HCl = CO2 + H2O + 2NaCl

OpenStudy (anonymous):

First you need to find the ionic equation. Separate all the reactants and products into their respective ions. Then, cancel out all spectators and you are left with the net ionic equation.

OpenStudy (anonymous):

would it be Na2CO3 + 2H+ 2Cl -> H2O + CO2 + 2Na +2Cl? Na2CO3 + 2H -> H2O + CO2 + 2Na

OpenStudy (anonymous):

@dimensionx

OpenStudy (anonymous):

Be sure to include positive and negative charges, you also need to separate the Na2CO3 into ions.

thomaster (thomaster):

Na2CO3 would split up in 2Na+ and CO3 2- So you can cancel out 2Na+ too That would leave 2H+(aq) + CO3-2(aq) --> H2O(l) + CO2(g)

OpenStudy (anonymous):

ohhhhh so i split the first one too? thanks

thomaster (thomaster):

Also don't forget the physical state symbols (g) (s) (l) (aq) and (cr) :P

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