i need to find derivative of (cos^3)(2x^4)
You need to use the Product Rule in this one.
And Chain Rule as well.
The part I'm having trouble with is the first part (cos^3) Would I use the derivative of cos which would be -sin or leave it as cos....
first do the derivative of the power and then cosine function
Yup, that's the Chain Rule.
so before it's simplified would it look like: (3(-sin^2) x (2x^4)) + (cos^3)(8x^3)
y r u using product rule? we need to apply only chain rule here
I'm confused as to what the outer function and the inner function is to use the chain rule...
first do the derivative of power then cosine function and after that term inside the cosine function For example :- we need to find the derivative of \[y = \sin^2(4x)\] first i m doing the derivative of power y' = 2sin(4x)* {sin(4x)}' = 2sin(4x) * cos(4x) * (4x)' = 2sin(4x)* cos(4x) * 4 NOTE:- ' symbol denotes the first derivative w.r.t x
if 4x is raised to the 3rd power in your original equation, would that change the process? so 4x^3 would become 12x^2?
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