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Mathematics 10 Online
OpenStudy (anonymous):

i need to find derivative of (cos^3)(2x^4)

Parth (parthkohli):

You need to use the Product Rule in this one.

Parth (parthkohli):

And Chain Rule as well.

OpenStudy (anonymous):

The part I'm having trouble with is the first part (cos^3) Would I use the derivative of cos which would be -sin or leave it as cos....

OpenStudy (anonymous):

first do the derivative of the power and then cosine function

Parth (parthkohli):

Yup, that's the Chain Rule.

OpenStudy (anonymous):

so before it's simplified would it look like: (3(-sin^2) x (2x^4)) + (cos^3)(8x^3)

OpenStudy (anonymous):

y r u using product rule? we need to apply only chain rule here

OpenStudy (anonymous):

I'm confused as to what the outer function and the inner function is to use the chain rule...

OpenStudy (anonymous):

first do the derivative of power then cosine function and after that term inside the cosine function For example :- we need to find the derivative of \[y = \sin^2(4x)\] first i m doing the derivative of power y' = 2sin(4x)* {sin(4x)}' = 2sin(4x) * cos(4x) * (4x)' = 2sin(4x)* cos(4x) * 4 NOTE:- ' symbol denotes the first derivative w.r.t x

OpenStudy (anonymous):

if 4x is raised to the 3rd power in your original equation, would that change the process? so 4x^3 would become 12x^2?

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