Question

An object is thrown directly up (positive direction) with a velocity (vo) of 20.0 m/s and do= 0. Determine how long it takes to get to the maximum height of 24.0 m.

Answer 1

at max height v= 0 so v^2 = u^2 - 2gs . v= 0 . so s = u^2/2g 20*20/2*10

Answer 2

does it include a formula?

Answer 3

yes its a formula where g = gravitational acceleration

Answer 4

40/20 is 2 is that the answer?

Answer 5

yes

Answer 6

no 200 is the answer check the calculation

Answer 7

`the answers i have that are close to 200 are 20.4 or 2.04

Answer 8

can you help me?

Answer 9

at highest point v=0
we know v=u - gt
g=9.8
u=20
v=0
t=u/g=20/9.8=2.04

Answer 10

u can also get by using formula s=u*t-.5*g*t^2
s=24
u=20
g=9.8
solve for t