An object is thrown directly up (positive direction) with a velocity (vo) of 20.0 m/s and do= 0. Determine how long it takes to get to the maximum height of 24.0 m.

Question

anonymous · Answer

at max height v= 0 so v^2 = u^2 - 2gs . v= 0 . so s = u^2/2g  20*20/2*10

anonymous · Answer

does it include a formula?

anonymous · Answer

yes its a formula where g = gravitational acceleration

anonymous · Answer

40/20 is 2 is that the answer?

anonymous · Answer

yes

anonymous · Answer

no 200 is the answer check the calculation

anonymous · Answer

`the answers i  have that are close to 200 are 20.4 or 2.04

anonymous · Answer

can you help me?

anonymous · Answer

at highest point v=0
we know v=u - gt
g=9.8
u=20
v=0
t=u/g=20/9.8=2.04

anonymous · Answer

u can also get by using formula s=u*t-.5*g*t^2
s=24
u=20
g=9.8
solve for t