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OpenStudy (anonymous):

Max values of a function

OpenStudy (anonymous):

\[E(t) = \frac{ 13500 }{ t+1 }\] \[L(t)=\frac{ 4500t+250 }{ t+1}\]

OpenStudy (anonymous):

\[126000 \] gallons at t=0

OpenStudy (anonymous):

E(t) and L(t) represent rates at which water enters/leaves the lake.

OpenStudy (anonymous):

Please help!

hartnn (hartnn):

can you take derivative ?

OpenStudy (anonymous):

I didnt think i had to bc the functions represent rates.

hartnn (hartnn):

to get max or min value, you need to equate the first derivative of the functions to 0

OpenStudy (anonymous):

Right but the functions already represent the derivative bc they're rates. Maybe im mistaken. But thats what ive been taught.

hartnn (hartnn):

ohh...can you post the entire question ?

OpenStudy (anonymous):

Sure, gimme a sec to type please.

OpenStudy (anonymous):

During a recent storm, water entered a lake through a stream and left through a spillway over a dam. The water entered at a rate given by the function \[E(t)=\frac{ 13500 }{ t+1 }\] and left the lake at a rate given by the function \[L(t)=\frac{ 4500t+250 }{ t+1 }\].. Both rates are in terms of gallons per hour and \[t\] is time in hours. At \[t=0\]the lake contained \[126000\] gallons of water.

OpenStudy (anonymous):

I did parts a,b, and c.

OpenStudy (anonymous):

Part d: At what time does the lake reach it maximum volume? Part e: What is the maximum volume of the lake?

hartnn (hartnn):

so, to get max. volume, e(t) should be maximum and l(t) should be minimum, right ??

hartnn (hartnn):

max, water should enter lake and min water shouldd leave the lake, to get max volume, make sense ? and yes, since they are rates, you'll just put t=0 in them.

OpenStudy (anonymous):

Ohh, that simple?

OpenStudy (anonymous):

So E(0) = 13500, L(0) =250

hartnn (hartnn):

no, actually, sorry. rates are to be equated to 0 so, e(t) =0 and l(t) = 0 actually, increase in volume will be proportional to e(t) - l (t) so, equate that to 0

hartnn (hartnn):

do you have answers to verify ?

OpenStudy (anonymous):

Thats what I did before. I did E(t)-L(t)=0, thus E(t)=L(t), when t= 2.944

hartnn (hartnn):

isn't that correct ?

OpenStudy (anonymous):

I wasnt sure.

hartnn (hartnn):

well, i get the same. so you can be sure now.

OpenStudy (anonymous):

Thanks. Brb

hartnn (hartnn):

part e) max volume = 126000+e(2.944)-l(2.944) see whether this makes sense.

OpenStudy (anonymous):

Ohh, hmm..ill try that.

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