Question

Can someone help?

Find the maximum y-value on the graph of y= f(x).

f(x) = -x^2 + 6x + 3

Answer 1

If you graph it, the max value is at (3, 12), so the max y value is 12...

Answer 2

thanks! @Amada

How would I graph this?
y = x^2 - 7

Answer 3

I know the graph is downward because of -7

Answer 4

You mean how to draw it, or how to graph it on a calculator?

Answer 5

Is what it should look like...

Answer 6

Draw it, Basically the question is this:

a)Sketch a graph of the equation.
b)identify the vertex
c)compare the graph of y=f(x) to the graph of y=x^2

Answer 7

You plug in points for x to get y values and then you plot them...so at x=-2, y=-3, x= -1, y=-6, etc...

Answer 8

The vertex point is a max or min, in this case the min is at x=0, y= -7

Answer 9

Just plot both graphs for part c...by plugging in values for x to find the y