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Precalculus 7 Online
OpenStudy (anonymous):

Find the product of z1 and z2 where z1 = 7(cos 40° + i sin 40°), and z2 = 6(cos 145° + i sin 145°).

OpenStudy (anonymous):

Use the law of De Moivre.

OpenStudy (anonymous):

Which means that scalar identities will get multiplied and angular/phase identities will get added.

OpenStudy (anonymous):

@Spacelimbus how do I set that up?

OpenStudy (anonymous):

Do you see the angles within the cos identities? When you multiply two complex numbers in polar form, these two angular identities just get added together.

OpenStudy (anonymous):

@Spacelimbus no

OpenStudy (anonymous):

just look at the cos(40°) and cos(145°) for now, what happens if you add these two angles together?

OpenStudy (anonymous):

@Spacelimbus i get -0.0532

OpenStudy (anonymous):

the first identities should be cos(40++145°)=cos(185°) now do the same with the sin.

OpenStudy (anonymous):

@spacelimbus 2sin185

OpenStudy (anonymous):

not 2 sin, just add the angles together. but the angle is right.

OpenStudy (anonymous):

so far you're at: (cos(185°)+isin(185°)) now all there is left to do is multiplying the factors in front

OpenStudy (anonymous):

@Spacelimbus 42(cos185+isin185) ?

OpenStudy (anonymous):

exactly

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