Mathematics
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OpenStudy (anonymous):
f(x)=-x^2+4x-4 four step method f(1)=? f(2)=? f(3)=?
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OpenStudy (anonymous):
can someone help me please!!
OpenStudy (anonymous):
r we finding for f(1), f(2) and f(3)?
OpenStudy (ivancsc1996):
Well, you only have to calculate using x=1......\[f(1)=-(1)^{2}+4(1)-4=1\]\[f(2)=-(2)^{2}+4(2)-4=8\]\[f(3)=?\]Try doing f(3) yourself.
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
is that the four step method?
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OpenStudy (anonymous):
lol so many steps?
OpenStudy (anonymous):
huh
OpenStudy (anonymous):
as ivancsc1996 showed, it can be done in one
OpenStudy (anonymous):
f'(x)=?
OpenStudy (anonymous):
f'(x)= -2x+4
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OpenStudy (ivancsc1996):
Oh that's the derivative which is what HawkCrimson showed.
OpenStudy (anonymous):
f(3)=13?
OpenStudy (ivancsc1996):
No, 17
OpenStudy (anonymous):
i though you subtract 4
OpenStudy (anonymous):
thought
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OpenStudy (ivancsc1996):
Oh no it is -1
OpenStudy (anonymous):
f(x)=-x^2+4x-4
f(3)=-(3)^2+4(3)-4
f(3)=-9 +12 -4
f(3) = -1
OpenStudy (anonymous):
thanks
OpenStudy (anonymous):
find the derivative of (13x^2-26x+26)e^-8x
OpenStudy (anonymous):
u'll have to use the product rule
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OpenStudy (anonymous):
ok
OpenStudy (anonymous):
so let u = (13x^2-26x+26) and v = e^-8x
where U(dv/dx) + V(du/dx)
OpenStudy (anonymous):
13(x^2-2x+2)e^-8x
OpenStudy (anonymous):
thats my answer
OpenStudy (anonymous):
ill do it now but that answer seems too similar to the question, did u use the product rule
V(du/dx) + U(dv/dx)?
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OpenStudy (anonymous):
yeah
OpenStudy (anonymous):
im looking at a similar one on my book idk if this is right but its my educated try
OpenStudy (anonymous):
ill tell u the answer in a sec, im almost done
OpenStudy (anonymous):
ok
OpenStudy (anonymous):
i got something different but i got big numbers lol ill show u my working
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OpenStudy (anonymous):
ok
OpenStudy (anonymous):
the question is find the derivative with respect to x if y
OpenStudy (anonymous):
so to find dy/dx?
OpenStudy (anonymous):
how i did it was like this
y = (13x^2-26x+26)e^-8x
and now im solving for dy/dx, isnt that wat u want?
OpenStudy (anonymous):
yes
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OpenStudy (anonymous):
U = 13x^2 - 26x + 26 V = e^-8x
du/dx = 26x - 26 dv/dx = -8e^-8x
OpenStudy (anonymous):
so thats the answer?
OpenStudy (anonymous):
no, that is half of the working
OpenStudy (anonymous):
oh ok
OpenStudy (anonymous):
V(du/dx) + U(dv/dx)
(e^-8x)(26x - 26) + (13x^2 - 26x + 26)( -8e^-8x)
2e^-8x [ (13x - 13) + -4(13x^2 - 26x + 26)
2e^-8x [ (13x - 13) + (-52x^2 + 104x - 104) ]
2e^-8x [ -52x^2 + 117x - 117 ]
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OpenStudy (anonymous):
I dont think its asking for that because i just did a similar problem (15x^3+9x^2+20x-4)^e-5x answer:(3x^3-4x)e^-5x
OpenStudy (anonymous):
I thought it was asking for the opposite way instead of solving
OpenStudy (anonymous):
lol so the question wasnt asking for dy/dx?
OpenStudy (anonymous):
the question is find the derivative with respect to x if y
OpenStudy (anonymous):
whatever that means
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OpenStudy (anonymous):
xD so wat method did u use?
OpenStudy (anonymous):
so r u saying my answer is wrong?
OpenStudy (anonymous):
product and chain rule
OpenStudy (anonymous):
idk it just look different than my book
OpenStudy (anonymous):
the answer in my book from the example problem i showed you
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OpenStudy (anonymous):
is it (15x^3+9x^2+20x-4)^e-5x or (15x^3+9x^2+20x-4)e^-5x ??