Question

Which equivalence factor set should you use to convert 2.68 x 1011 atoms of Ag to grams of Ag?
(Points : 3)

(2.68 x 1011 atoms Ag/1 mol Ag)(1 mol Ag/107.88 g Ag)


(1 mol Ag/2.68 x 1011 atoms Ag)(107.88 g Ag/1 mol Ag)


(1 mol Ag/6.02 x 1023 atoms Ag)(107.88 g Ag/1 mol Ag)


(2.68 x 1011 atoms Ag/6.02 x 1023 atoms Ag)(107.88 g Ag)

Answer 1

To convert atoms to grams ,you should do the following :
1-divide the number of atoms by Avogadro's number (6.022x10^23) (In order to change it to moles)
2-Multiply the result by the atomic weight .
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Can you follow the steps ?

Answer 2

So it would be the third? or am I actually working out the equation ?

Answer 3

It should be
(2.68 x 1011/6.022x0^23) x 107.8682

Answer 4

Got it ?

Answer 5

Oh yes yes, now I see... shouldn't have jumped to conlusion!