Determine the area under the standard normal curve that lies to the right of the following z score. Use a table if necessary. Round your answer to four decimal places. z = –1.62
Madam is the Question Comple, it seems that some more data are required for solving the answer.
That's the whole question
Ok then let me and @nader1 try it.
Lies to the right....
Do you have a standard normal table? This can also be calculated precisely using a calculator that has statistics functions.
So clearly we know: \[ \Phi(z) \]Is the area to the left, and we know that the total area is \(1\).
http://www.danielsoper.com/statcalc3/calc.aspx?id=2 It gave a value correct to 7 decimal places. My TI-84 computes it out to 10 places. Most statistical tables will only provide 4 or 5 decimal digits of accuracy, which is usually sufficient.
So the area to the right is just: \[ 1-\Phi(z) = 1-\Phi(-1.62) \]
You find \(\Phi(z)\) by looking up \(z\) in a \(z\)-table.
@bcaronna Does this make sense?
you will find z=1.57
yeah I think so.. it's that easy? so what if it were asking for the are to the left?
Okay, once again. The area to the left is: \[ A_{left}=\Phi(z) \]The total area is \[ A_{total}=1\]The total area is the sum of the right and left areas: \[ A_{left}+A_{right} =A_{total} \implies \Phi(z) + A_{right} = 1 \implies A_{right}= 1-\Phi(z) \]
how do I find Φ(z)
what is Φ ?
is the answer .9473 ?
z=1.57 the answer
that's the area under that standard normal curve?
yea
@msumner @msumner @msumner
that doesn't make sense. 0.05261614 is what I got when I put -1.62 into the link you sent me
so isn't it 1 - 0.05261614
it impossible z= -1.62
you should findthat z =1.57
how ??? it literally says in the original problem that z = -1.62
are you sure it is -.1.62?
bro, scroll up and look at the problem it says z = -1.62
because people have same given but z =1.57 it work with link mmm that strange let me see then
lol never mind man I figured it out thank you anyways
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