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Mathematics 12 Online
OpenStudy (anonymous):

Determine the area under the standard normal curve that lies to the right of the following z score. Use a table if necessary. Round your answer to four decimal places. z = –1.62

OpenStudy (goformit100):

Madam is the Question Comple, it seems that some more data are required for solving the answer.

OpenStudy (anonymous):

That's the whole question

OpenStudy (goformit100):

Ok then let me and @nader1 try it.

OpenStudy (anonymous):

Lies to the right....

OpenStudy (anonymous):

Do you have a standard normal table? This can also be calculated precisely using a calculator that has statistics functions.

OpenStudy (anonymous):

So clearly we know: \[ \Phi(z) \]Is the area to the left, and we know that the total area is \(1\).

OpenStudy (anonymous):

http://www.danielsoper.com/statcalc3/calc.aspx?id=2 It gave a value correct to 7 decimal places. My TI-84 computes it out to 10 places. Most statistical tables will only provide 4 or 5 decimal digits of accuracy, which is usually sufficient.

OpenStudy (anonymous):

So the area to the right is just: \[ 1-\Phi(z) = 1-\Phi(-1.62) \]

OpenStudy (anonymous):

You find \(\Phi(z)\) by looking up \(z\) in a \(z\)-table.

OpenStudy (anonymous):

@bcaronna Does this make sense?

OpenStudy (anonymous):

you will find z=1.57

OpenStudy (anonymous):

yeah I think so.. it's that easy? so what if it were asking for the are to the left?

OpenStudy (anonymous):

Okay, once again. The area to the left is: \[ A_{left}=\Phi(z) \]The total area is \[ A_{total}=1\]The total area is the sum of the right and left areas: \[ A_{left}+A_{right} =A_{total} \implies \Phi(z) + A_{right} = 1 \implies A_{right}= 1-\Phi(z) \]

OpenStudy (anonymous):

how do I find Φ(z)

OpenStudy (anonymous):

what is Φ ?

OpenStudy (anonymous):

is the answer .9473 ?

OpenStudy (anonymous):

z=1.57 the answer

OpenStudy (anonymous):

that's the area under that standard normal curve?

OpenStudy (anonymous):

yea

OpenStudy (anonymous):

@msumner @msumner @msumner

OpenStudy (anonymous):

that doesn't make sense. 0.05261614 is what I got when I put -1.62 into the link you sent me

OpenStudy (anonymous):

so isn't it 1 - 0.05261614

OpenStudy (anonymous):

it impossible z= -1.62

OpenStudy (anonymous):

you should findthat z =1.57

OpenStudy (anonymous):

how ??? it literally says in the original problem that z = -1.62

OpenStudy (anonymous):

are you sure it is -.1.62?

OpenStudy (anonymous):

bro, scroll up and look at the problem it says z = -1.62

OpenStudy (anonymous):

because people have same given but z =1.57 it work with link mmm that strange let me see then

OpenStudy (anonymous):

lol never mind man I figured it out thank you anyways

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