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Geometry 7 Online
OpenStudy (anonymous):

find the value of x i said its 8 the picture is attached

OpenStudy (anonymous):

OpenStudy (goformit100):

Wow, there is a theorem for it , do you know that ?

OpenStudy (anonymous):

theorem 10.15 isnt it i dnt get it tho in my book there is something else and the question is one step more

OpenStudy (anonymous):

how did you find 8?

OpenStudy (anonymous):

to be honest i dnt kno i kept lookin in the textbook at all te theorems nd i didnt gt it im sure its theorem 10.15 but im not gettin it

OpenStudy (anonymous):

no angle in the given?

OpenStudy (anonymous):

its just what i posted i tried to make a triangle out of it it didnt work

Directrix (directrix):

The theorem you need is attached. If two secant segments are drawn to a circle from an outside point, then the length of one secant segment times the length of the exterior portion of the secant segment is equal the the product of the other secant segment times its exterior portion.

Directrix (directrix):

That means that in your problem, x(7+x) = 6(6+4) 7x + x² = 60 x² + 7x - 60 = 0 Factor and solve for x. @nisa

OpenStudy (anonymous):

i did this (7+x)*x=(4+6)*6 7x*x=10*6 \[(7+x)timesx=(4+6)\times6 \] \[\sqrt{7x ^{2}}=\sqrt{60}\] \[7x \div7=7.74\div7\] x=1.1

Directrix (directrix):

@nisa (7+x)*x=(4+6)*6 --> Error: (7+x)  ≠ (7x) 7x*x=10*6 -------------------- x² + 7x - 60 = 0 (x - 5) * (x + 12) = 0 Use the Zero Product Property x - 5 = 0 or x + 12 = 0 Solve each of these for x.

OpenStudy (anonymous):

im confused where did the zero property come from?

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