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f(x)= ^3√x-9 find f^-1(x)
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Is that the inverse of a cube root function?
idk thats how it was written. simplify answer
I'm trying to check how you have typed it up. It's not totally clear to me, but assuming that is.... To find the inverse you switch the x and y terms and simplify.
\[ f(x)=\sqrt[3]{x-9} \]To find \(f^{-1}(x)\) we replace \(f(x)\) with \(x\) and \(x\) with \(f^{-1}(x)\):\[ x=\sqrt[3]{f^{-1}(x)-9} \]Then you must solve for \(f^{-1}(x)\).
Cube both sides:\[ x^3=f^{-1}(x)-9 \]Add 9 to both sides:\[ f^{-1}(x) = x^3+9 \]
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