Simplify 8 to the power of negative 4 over 3

Question

anonymous · Answer

@campbell_st

campbell_st · Answer

so you need to know 

$$8 = 2^3$$

and the question is asking you to simplify 

$$8^{-\frac{4}{3}} = (2^3)^{-\frac{4}{3}}$$

there you go... just use the power of a power rule described in your last question.

campbell_st · Answer

oh... and you will need to know about negative powers

$$x^{-a} = \frac{1}{x^a}$$

anonymous · Answer

so ?

campbell_st · Answer

I'm not answering it... I'm giving you advice on how you can answer it. 

Hope it helps.

anonymous · Answer

@campbell_st  im in dire need of your assitance dont leave me stranded

campbell_st · Answer

so here is my work again

$$8 = 2^3$$

a refresher on power of a power

$$(x^a)^b = x^{a \times b}$$

so you have 

$$8^{-\frac{4}{3}} = (2^3)^{-\frac{4}{3}}$$

now hopefully you can simplify it.

campbell_st · Answer

don't forget to scroll up... and look at negative powers..