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Mathematics 16 Online
OpenStudy (anonymous):

find dy/dx of y=tan^2(e^x)

OpenStudy (abb0t):

Chain rule.

OpenStudy (aravindg):

yep :)

OpenStudy (aravindg):

do you know how to do chain rule @candiwonderland ?

OpenStudy (abb0t):

It might help if you think of it like this: \([\tan(e^x)]^2\) in which case you do derivative of the outside times derivative of the inside: \(e^x\)

OpenStudy (anonymous):

yeah but i dont know the deriv of tan^2

OpenStudy (aravindg):

apply chain rule ! assume t=tant x first find derivative of t^2 ie 2t

OpenStudy (anonymous):

is it sec^2?

OpenStudy (abb0t):

YES.

OpenStudy (abb0t):

BUT, you have to start from the outside first. That's how the chain rule works. Derivative of the ousdie. and notice that tangent is squared.

OpenStudy (aravindg):

now multiply with derivative of tan x to complete chain rule for tan^2 x

OpenStudy (anonymous):

so its sex^2(e^x) x e^x

OpenStudy (anonymous):

sec*

OpenStudy (abb0t):

Close, but not quite. You have to take the derivative of outside of tangent first :)

OpenStudy (aravindg):

check what I said above

OpenStudy (aravindg):

assume t=tant x first find derivative of t^2 ie 2t

OpenStudy (aravindg):

now multiply with derivative of tan x to complete chain rule for tan^2 x

OpenStudy (abb0t):

\([\tan(x)]^2\) where \(x=e^x\)

OpenStudy (aravindg):

yep ^^

OpenStudy (anonymous):

ohhhhhhh

OpenStudy (aravindg):

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