Given the following unbalanced chemical equation, how many grams of aluminum chloride are produced when 3.00 moles of aluminum reacts with 5.30 moles of chlorine gas? ___Al + ___ Cl2 arrow ___AlCl3
471 grams 399 grams 151 grams 177 grams
can u tell molecular weight of Al Cl2 and AlCl3
AI- 26.98153868 CI2- 70.9064 AICI3- 133.3411
anc can you balance the reaction and write it
I do not think so
mean u dont know
yes, I do not know lol
:)
help! lol :)
2Al + 3Cl2 = 2AlCl3 is a balanced equation
wow I was sooooooo off.... how do I figure out grams now?
for 2 moles of Al how many moles of Cl2 is required can you tell
3?
yaaa right
yay! now what?
now you have to check which one is limiting reagent
oh gosh... I would say CI2
mean Cl2 is in excess than the Al right bcoz 2 mole of Al needs 3moles of Cl2 from balanced equation but in ur question they have mentioned for 3 moles of Al reacts with 5.30 moles since Cl2 is huge amount hence it is not limiting reagent limiting reagent is Al
2mole s of Al give rise too 2 moles of alCl3 3 moles of Al give rise too =3*2 /2 =3 moles of AlCl3 u have to convert moles into grams grams = moles * molecular weight of AlCl3 = 3 * 133.34 = 400 gram
can u guess the answer now
the only one that comes close is 399...
yaaa that is the answer LOL:)
OH!! AWESOME!
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