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Using the Product Rule, find the derivative of the following: f(x)=(x^3-3x+4)(2x-1)
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@Callisto can you help
\[f'(x)= (3x-3)(2x-1)+(x ^{3}-3x+4)(2x)=6x ^{2}-9x+3+2x ^{4}-6x ^{2}+8x=2x ^{4}-9x+3\]
you can finish combining the like terms.
can you explain so i know how to do it on my own next time
well we use the product rule and that states that f'(x) = the derivative of the 1st function times the 2nd function plus the derivative of the 2nd function times the 1st function.
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do you get it?
yes.... so for the next problem i would do \[(3x ^{2})(x ^{2}-1)+(x ^{3})(2x)\]
whats the next problem?
that seems right if the problem is f(x)=x^3(x^2-1)
Hope that helps!
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yup thank you mucho
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