Given the following chemical equation, if 162.0 grams of potassium reacts with excess oxygen gas and was found to produce 172 grams of potassium oxide, what is the percent yield for this reaction?
4 K(s) + O2(g) arrow 2K2O(s)
(Points : 3)

44%

75%

22%

88%

Question

Given the following chemical equation, if 162.0 grams of potassium reacts with excess oxygen gas and was found to produce 172 grams of potassium oxide, what is the percent yield for this reaction?
4 K(s) + O2(g) arrow 2K2O(s)
 (Points : 3)  
       
44%

        
75%

        
22%

        
88%

anonymous · Answer

I guessed 88% but I am 99% sure that is wrong lol

chmvijay · Answer

can u tell me molecular weight of potassium and potassium oxide

anonymous · Answer

Potassium- 39.09 Potassium Oxide- 94.2

chmvijay · Answer

188.4 gram of K2O should be formed for 100% yield 
then in this case  172 gram is formed 
188.4 gram = 100 % 
172 gram = 100*172 / 188.4 = 91.3 % i am getting

chmvijay · Answer

is the options are right pleas e check once LOL:(

anonymous · Answer

The answers are right..

anonymous · Answer

88%?

chmvijay · Answer

yaaa may be !!! near value is this one only 1!!