Given the following chemical equation, if 50.1 grams of silicon dioxide is heated with excess carbon and 32.3 grams of silicon carbide is produced, what is the percent yield for this reaction?
SiO2 (s) + 3C (s) arrow SiC (s) + 2CO (g)
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OpenStudy (anonymous):
97%
75%
103%
48%
OpenStudy (chmvijay):
molecular weight of SI C ???
OpenStudy (anonymous):
SI- 28.08 C-12.01
OpenStudy (chmvijay):
LOL:) how did u calculate let me know??
OpenStudy (anonymous):
Percentage Yield = mass of Actual Yield/mass of Theoretical Yield x 100%
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OpenStudy (chmvijay):
but its coming around 80 % in this case
OpenStudy (chmvijay):
32.03/40 *100 =80.75 %
OpenStudy (anonymous):
This is why I have you!
OpenStudy (chmvijay):
i dont know the options u have took from !!!1???
OpenStudy (chmvijay):
u told 97 % how u got that
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OpenStudy (anonymous):
51.1/32.4 x 100... I was wrong
OpenStudy (anonymous):
50.1***
OpenStudy (anonymous):
32.3***
OpenStudy (chmvijay):
does weight of reactant has any role in this i dont think sooo LOL:(
OpenStudy (anonymous):
yeah... :( chemistry does not like me... but 80.75% isn't a choice... either...
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OpenStudy (chmvijay):
:)
OpenStudy (chmvijay):
sory i cant any more such questions :(
OpenStudy (anonymous):
That is okay that was the last one of that type I think...