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Chemistry 14 Online
OpenStudy (anonymous):

Given 4.8 moles of a gas in a 1.8 L container, if the temperature is found to be 31 degrees Celsius, what is the pressure of the gas? (The ideal gas constant is 0.0821 L · atm/mol · K and 1 atm = 760 torr.) 6.79 torr 66.55 torr 6.79 x 100 atm 6.66 x 101 atm

OpenStudy (anonymous):

6.79 x 10^0 6.66 x 10^1

OpenStudy (chmvijay):

use PV= nrt equation LOL:)

OpenStudy (dean.shyy):

Take a look at this: http://is.gd/didXYL

OpenStudy (unklerhaukus):

\[PV=nRT\]\[P=\frac{nRT}V\] \[n=4.8 [\text{mol}]\]\[V=1.8 [\text L]\]\[T=31 [°\text C]= 304.15 [\text{K}]\]\[R=0.0821 [\text{L·atm/mol·K}] \]

OpenStudy (chmvijay):

LOL:) got it or nooo

OpenStudy (anonymous):

it is a little late now, thank you all for all of the help I sooo soo soo much appreciate it!

OpenStudy (chmvijay):

ur welcome :)

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