limx->1+ (sqrt{x^{2}-x}/x-x^{2})
\[\lim_{x \rightarrow 1} (\sqrt{x ^{2}-x} ) /x-x ^{2}\]
is the question, \(\large \lim \limits_{x \rightarrow 1^+} \dfrac{(\sqrt{x ^{2}-x} )}{ x-x ^{2}} \)
@hartnn, I would think so, since most of the time homework problems give indeterminate form.
@hartnn yes it is.
ok, then use \(y= \sqrt y \times \sqrt y\) what about \((x-x^2)=...?\) anything cancels out ?
or rather, factor out - *minus* first, -(x^2-x)
i got 1/0.
oh, you actually get, \(\large \lim \limits_{x \rightarrow 1^+} \dfrac{1}{-(\sqrt{ x^2-x })}\) right ? now what about the denominator ? when x->1+, x is very very near to 1 but \(\large x>1\) so, denominator will be positive or negative ?
negative. so is it -infty ?
YES, correct :)
thank you :). i have one more question. can i mention you when i write ?
yes, you can, and i saw that limit , tends to 3, right....
yes. and i have one more which is i'm going to write now.
ok, sure.
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